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-2x^2-13x-19=0
a = -2; b = -13; c = -19;
Δ = b2-4ac
Δ = -132-4·(-2)·(-19)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{17}}{2*-2}=\frac{13-\sqrt{17}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{17}}{2*-2}=\frac{13+\sqrt{17}}{-4} $
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